222 lines
		
	
	
		
			8.8 KiB
		
	
	
	
		
			C++
		
	
	
			
		
		
	
	
			222 lines
		
	
	
		
			8.8 KiB
		
	
	
	
		
			C++
		
	
	
| /*
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|  * QPSolver.h
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|  * @brief: A quadratic programming solver implements the active set method
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|  * @date: Apr 15, 2014
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|  * @author: thduynguyen
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|  */
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| 
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| #pragma once
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| 
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| #include <gtsam/linear/VectorValues.h>
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| #include <gtsam_unstable/linear/QP.h>
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| 
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| #include <vector>
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| #include <set>
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| 
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| namespace gtsam {
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| 
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| /// This struct holds the state of QPSolver at each iteration
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| struct QPState {
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|   VectorValues values;
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|   VectorValues duals;
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|   LinearInequalityFactorGraph workingSet;
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|   bool converged;
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| 
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|   /// default constructor
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|   QPState() :
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|       values(), duals(), workingSet(), converged(false) {
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|   }
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| 
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|   /// constructor with initial values
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|   QPState(const VectorValues& initialValues, const VectorValues& initialDuals,
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|       const LinearInequalityFactorGraph& initialWorkingSet, bool _converged) :
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|       values(initialValues), duals(initialDuals), workingSet(initialWorkingSet), converged(
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|           _converged) {
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|   }
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| };
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| 
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| /**
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|  * This class implements the active set method to solve quadratic programming problems
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|  * encoded in a GaussianFactorGraph with special mixed constrained noise models, in which
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|  * a negative sigma denotes an inequality <=0 constraint,
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|  * a zero sigma denotes an equality =0 constraint,
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|  * and a positive sigma denotes a normal Gaussian noise model.
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|  */
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| class QPSolver {
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| 
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|   const QP& qp_; //!< factor graphs of the QP problem, can't be modified!
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|   GaussianFactorGraph baseGraph_; //!< factor graphs of cost factors and linear equalities. The working set of inequalities will be added to this base graph in the process.
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|   VariableIndex costVariableIndex_, equalityVariableIndex_,
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|       inequalityVariableIndex_;
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|   FastSet<Key> constrainedKeys_; //!< all constrained keys, will become factors in the dual graph
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| 
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| public:
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|   /// Constructor
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|   QPSolver(const QP& qp);
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| 
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|   /// Find solution with the current working set
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|   VectorValues solveWithCurrentWorkingSet(
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|       const LinearInequalityFactorGraph& workingSet) const;
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| 
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|   /// @name Build the dual graph
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|   /// @{
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| 
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|   /// Collect the Jacobian terms for a dual factor
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|   template<typename FACTOR>
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|   std::vector<std::pair<Key, Matrix> > collectDualJacobians(Key key,
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|       const FactorGraph<FACTOR>& graph,
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|       const VariableIndex& variableIndex) const {
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|     std::vector<std::pair<Key, Matrix> > Aterms;
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|     if (variableIndex.find(key) != variableIndex.end()) {
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|       BOOST_FOREACH(size_t factorIx, variableIndex[key]){
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|         typename FACTOR::shared_ptr factor = graph.at(factorIx);
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|         if (!factor->active()) continue;
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|         Matrix Ai = factor->getA(factor->find(key)).transpose();
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|         Aterms.push_back(std::make_pair(factor->dualKey(), Ai));
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|       }
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|     }
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|     return Aterms;
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|   }
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| 
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|   /// Create a dual factor
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|   JacobianFactor::shared_ptr createDualFactor(Key key,
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|       const LinearInequalityFactorGraph& workingSet,
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|       const VectorValues& delta) const;
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| 
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|   /**
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|    * Build the dual graph to solve for the Lagrange multipliers.
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|    *
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|    * The Lagrangian function is:
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|    *        L(X,lambdas) = f(X) - \sum_k lambda_k * c_k(X),
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|    * where the unconstrained part is
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|    *        f(X) = 0.5*X'*G*X - X'*g + 0.5*f0
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|    * and the linear equality constraints are
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|    *        c1(X), c2(X), ..., cm(X)
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|    *
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|    * Take the derivative of L wrt X at the solution and set it to 0, we have
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|    *    \grad f(X) = \sum_k lambda_k * \grad c_k(X)   (*)
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|    *
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|    * For each set of rows of (*) corresponding to a variable xi involving in some constraints
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|    * we have:
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|    *    \grad f(xi) = \frac{\partial f}{\partial xi}' = \sum_j G_ij*xj - gi
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|    *    \grad c_k(xi) = \frac{\partial c_k}{\partial xi}'
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|    *
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|    * Note: If xi does not involve in any constraint, we have the trivial condition
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|    * \grad f(Xi) = 0, which should be satisfied as a usual condition for unconstrained variables.
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|    *
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|    * So each variable xi involving in some constraints becomes a linear factor A*lambdas - b = 0
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|    * on the constraints' lambda multipliers, as follows:
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|    *    - The jacobian term A_k for each lambda_k is \grad c_k(xi)
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|    *    - The constant term b is \grad f(xi), which can be computed from all unconstrained
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|    *    Hessian factors connecting to xi: \grad f(xi) = \sum_j G_ij*xj - gi
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|    */
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|   GaussianFactorGraph::shared_ptr buildDualGraph(
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|       const LinearInequalityFactorGraph& workingSet,
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|       const VectorValues& delta) const;
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| 
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|   /// @}
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| 
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|   /**
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|    * The goal of this function is to find currently active inequality constraints
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|    * that violate the condition to be active. The one that violates the condition
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|    * the most will be removed from the active set. See Nocedal06book, pg 469-471
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|    *
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|    * Find the BAD active inequality that pulls x strongest to the wrong direction
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|    * of its constraint (i.e. it is pulling towards >0, while its feasible region is <=0)
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|    *
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|    * For active inequality constraints (those that are enforced as equality constraints
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|    * in the current working set), we want lambda < 0.
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|    * This is because:
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|    *   - From the Lagrangian L = f - lambda*c, we know that the constraint force
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|    *     is (lambda * \grad c) = \grad f. Intuitively, to keep the solution x stay
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|    *     on the constraint surface, the constraint force has to balance out with
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|    *     other unconstrained forces that are pulling x towards the unconstrained
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|    *     minimum point. The other unconstrained forces are pulling x toward (-\grad f),
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|    *     hence the constraint force has to be exactly \grad f, so that the total
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|    *     force is 0.
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|    *   - We also know that  at the constraint surface c(x)=0, \grad c points towards + (>= 0),
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|    *     while we are solving for - (<=0) constraint.
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|    *   - We want the constraint force (lambda * \grad c) to pull x towards the - (<=0) direction
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|    *     i.e., the opposite direction of \grad c where the inequality constraint <=0 is satisfied.
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|    *     That means we want lambda < 0.
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|    *   - This is because when the constrained force pulls x towards the infeasible region (+),
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|    *     the unconstrained force is pulling x towards the opposite direction into
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|    *     the feasible region (again because the total force has to be 0 to make x stay still)
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|    *     So we can drop this constraint to have a lower error but feasible solution.
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|    *
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|    * In short, active inequality constraints with lambda > 0 are BAD, because they
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|    * violate the condition to be active.
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|    *
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|    * And we want to remove the worst one with the largest lambda from the active set.
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|    *
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|    */
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|   int identifyLeavingConstraint(
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|       const LinearInequalityFactorGraph& workingSet,
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|       const VectorValues& lambdas) const;
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| 
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|   /**
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|    * Compute step size alpha for the new solution x' = xk + alpha*p, where alpha \in [0,1]
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|    *
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|    *    @return a tuple of (alpha, factorIndex, sigmaIndex) where (factorIndex, sigmaIndex)
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|    *            is the constraint that has minimum alpha, or (-1,-1) if alpha = 1.
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|    *            This constraint will be added to the working set and become active
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|    *            in the next iteration
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|    */
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|   boost::tuple<double, int> computeStepSize(
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|       const LinearInequalityFactorGraph& workingSet, const VectorValues& xk,
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|       const VectorValues& p) const;
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| 
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|   /** Iterate 1 step, return a new state with a new workingSet and values */
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|   QPState iterate(const QPState& state) const;
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| 
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|   /**
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|    * Identify active constraints based on initial values.
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|    */
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|   LinearInequalityFactorGraph identifyActiveConstraints(
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|       const LinearInequalityFactorGraph& inequalities,
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|       const VectorValues& initialValues) const;
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| 
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|   /** Optimize with a provided initial values
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|    * For this version, it is the responsibility of the caller to provide
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|    * a feasible initial value, otherwise the solution will be wrong.
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|    * If you don't know a feasible initial value, use the other version
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|    * of optimize().
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|    * @return a pair of <primal, dual> solutions
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|    */
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|   std::pair<VectorValues, VectorValues> optimize(
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|       const VectorValues& initialValues) const;
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| 
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|   /** Optimize without an initial value.
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|    * This version of optimize will try to find a feasible initial value by solving
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|    * an LP program before solving this QP graph.
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|    * TODO: If no feasible initial point exists, it should throw an InfeasibilityException!
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|    * @return a pair of <primal, dual> solutions
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|    */
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|   std::pair<VectorValues, VectorValues> optimize() const;
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| 
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|   /**
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|    * find the max key
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|    */
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|   std::pair<bool, Key> maxKey(const FastSet<Key>& keys) const;
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| 
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|   /**
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|    * Create initial values for the LP subproblem
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|    * @return initial values and the key for the first and last slack variables
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|    */
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|   boost::tuple<VectorValues, Key, Key> initialValuesLP() const;
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| 
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|   /// Create coefficients for the LP subproblem's objective function as the sum of slack var
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|   VectorValues objectiveCoeffsLP(Key firstSlackKey) const;
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| 
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|   /// Build constraints and slacks' lower bounds for the LP subproblem
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|   boost::tuple<LinearEqualityFactorGraph::shared_ptr,
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|       LinearInequalityFactorGraph::shared_ptr, VectorValues> constraintsLP(
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|       Key firstSlackKey) const;
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| 
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|   /// Find a feasible initial point
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|   std::pair<bool, VectorValues> findFeasibleInitialValues() const;
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| 
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| };
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| 
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| } /* namespace gtsam */
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