Removed a spurious commented line and included a comment about what the K value signifies.
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2e8dcdd410
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2430917e03
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@ -125,7 +125,10 @@ def plot_point2_on_axes(axes,
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if P is not None:
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w, v = np.linalg.eig(P)
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# k = 2.296
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# "Sigma" value for drawing the uncertainty ellipse. 5 sigma corresponds
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# to a 99.9999% confidence, i.e. assuming the estimation has been
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# computed properly, there is a 99.999% chance that the true position
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# of the point will lie within the uncertainty ellipse.
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k = 5.0
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angle = np.arctan2(v[1, 0], v[0, 0])
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